C# Program to find Area of Triangle

C# Program to find Area of Triangle

Program Statement:

If the lengths of the sides of a triangle are denoted by a, b, and c, then area of triangle is given by

Area = SS(S-a)(S-b)(S-c)

where, S = ( a + b + c ) / 2

Solution:

 class sq
    {
        int a, b, c;
        double S, Area, temp2;
        public double s(double t)
        {
            double lb = 0, ub = t, temp = 0; int count = 50;
            while (count != 0)
            {
                temp = (lb + ub) / 2;
                if (temp * temp == t)
                { return temp; }
                else if (temp * temp > t)
                { ub = temp; }
                else
                { lb = temp; }
                count--;
            }
            return temp;
        }
        public void cal()
        {
            Console.Write("\n\t\tEnter value of a : ");
            a = Convert.ToInt32(Console.ReadLine());
            Console.Write("\n\t\tEnter value of b : ");
            b = Convert.ToInt32(Console.ReadLine());
            Console.Write("\n\t\tEnter value of c : ");
            c = Convert.ToInt32(Console.ReadLine());
            S = (a + b + c) / 2;
            temp2 = (S * (S - a) * (S - b) * (S - c));
            Area = S * s(temp2);
            Console.WriteLine("\n\t\tArea = {0}\n\n", Area);
        }
    }